(-2y+1)^2=-2(y+3)+2

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Solution for (-2y+1)^2=-2(y+3)+2 equation: 



(-2y+1)^2=-2(y+3)+2

We move all terms to the left:

(-2y+1)^2-(-2(y+3)+2)=0



We calculate terms in parentheses: -(-2(y+3)+2), so:

-2(y+3)+2

We multiply parentheses

-2y-6+2

We add all the numbers together, and all the variables

-2y-4

Back to the equation:

-(-2y-4)



We get rid of parentheses

(-2y+1)^2+2y+4=0

We add all the numbers together, and all the variables

2y+(-2y+1)^2+4=0

We move all terms containing y to the left, all other terms to the right

2y+(-2y+1)^2=-4

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